## LeetCode 681. Next Closest Time in Java

In this post we will solve LeetCode 681. Next Closest Time problem using the Java programming language, the VSCode IDE on a Windows computer. Please note that the computer platform and the IDE should make no difference. One of the simplest ways to solve the problem is to use the online IDE provided by LeetCode.

```Given a time represented in the format "HH:MM",
form the next closest time by reusing the current digits.
There is no limit on how many times a digit can be reused.

You may assume the given input string is always valid.
For example, "01:34", "12:09" are all valid.
"1:34", "12:9" are all invalid.

Constraints:

* time.length == 5
* time is a valid time in the form "HH:MM".
o 0 <= HH < 24
o 0 <= MM < 60

Related Topics:

o String
o Enumeration
```

We are given a string with a time expressed in 24-hour format. By reusing the digits as many times as needed, we need to form the next closest time. Continue reading “LeetCode 681. Next Closest Time in Java”

## LeetCode 949. Largest Time for Given Digits in Java

In this post we will solve the LeetCode 949. Largest Time for Given Digits problem using the Java programming language and the VSCode IDE on a Windows computer.

```Given an array arr of 4 digits,
find the latest 24-hour time that can be made using each digit exactly once.

24-hour times are formatted as "HH:MM",
where HH is between 00 and 23,
and MM is between 00 and 59.
The earliest 24-hour time is 00:00, and the latest is 23:59.

Return the `latest`di 24-hour time in "HH:MM" format.
If no valid time can be made, return an empty string.

Related Topics:

o String
o Enumeration
```

We are given an int[] array with four digits. We need to find the latest 24-hour time using exactly each digit once and return the results using the HH:MM format. Continue reading “LeetCode 949. Largest Time for Given Digits in Java”